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Introduction 3.3.1
Now we take a look at a few theorems without proof (the proofs involve
ideas of compactness and closedness of sets that would lead us too far away
from the essence of these lecture notes). These theorems are intuitively
very reasonable and you can convince yourself that they do make sense by trying
to graph a couple counterexamples.
Theorem 3.3.2 (Weierstrass)
If
![$ f : [a,b] \to \hbox {I \hskip -5.2pt {R}}$](img285.png)
is a continuous function,
then

attains a minimum and a maximum within the interval
![$ [a,b]$](img286.png)
.
Remark 3.3.3
The picture you should have in mind when thinking about Weierstrass' theorem should
be something like:
180pt
The fact that

is continuous excludes functions like

considered
over the interval
![$ [-1,1]$](img37.png)
. In this case, the the maximum is

and the
minimum

. Also note that the theorem no longer works if we consider open
intervals. Take e.g. again the function

, but over the interval
![$ ]0,1]$](img288.png)
. Over this interval, the function is continuous, and yet, the maximum
is infinity.
Theorem 3.3.4 (Bolzano (a.k.a. Mean Value Theorem))
If
![$ f : [a,b] \to \hbox {I \hskip -5.2pt {R}}$](img285.png)
is a continuous function, then

attains all values
between

and

.
Remark 3.3.5
Discontinuous functions will rarely work for Bolzano's theorem as
the following picture indicates:
180pt
Clearly, There is no

such that

.
The converse is obviously not true. A function that attains all values between

and

is not necessarily continuous, as the following picture of the

function convincingly illustrates:
200pt
Corollary 3.3.6 (Root Existence Theorem)
If

is continuous over
![$ [a,b]$](img286.png)
and

, meaning that one is
positive and the other is negative, then there exists at least one

in
![$ ]a,b[$](img296.png)
for which

.
Next: Differentiation
Up: Continuous Functions
Previous: Calculation of Limits
  Contents
Marc Corluy
2003-08-26